HELPPP MEEEEEEE!!!!!!!! plzWhich ordered pairs are solutions to the inequality 2x+3y≥−1 ?Select each correct answer.(2, −1)(−6, 0)(−2, 1)(0, 1)(0, −1)

Answer:(2,-1)(-2,1)(0,1)Step-by-step explanation:Let's plug in the points given and see which satisfy it (make it true).2x+3y>=-1Test (2,-1)2(2)+3(-1)>=-14    + (-3)>=-1            1>=-1  This is true 1 is greater than -1 so (2,-1) works!Test (-6,0)2(-6)+3(0)>=-1-12   +  0  >=-1          -12 >=-1 This is not true. -12 is not greater than -1.Test (-2,1)2(-2)+3(1)>=-1 -4   +  3 >=-1          -1 >=-1  This is true. -1 does equal -1.Test (0,1)2(0)+3(1)>=-1  0  +  3 >=-1          3>=-1  This is true.  3 is greater than -1.Test (0,-1)2(0)+3(-1)>=-1 0   + (-3)>=-1          -3>=-1  This is false.  -3 is not greater than -1.